Найдите значение выражения:
а)

4 \frac{11}{18} * \frac{6}{7} - 1 \frac{4}{9}

;
б)

(1 \frac{1}{2})^{3} - 2 \frac{1}{4} * 1 \frac{1}{3}

;
в)

((1 \frac{1}{4})^{2} - \frac{5}{8}) * 10 \frac{2}{3} - 7 \frac{1}{3}

;
г)

(1 \frac{4}{9} + 2 \frac{5}{6} - 2 \frac{3}{4}) * (2 \frac{1}{2} - \frac{11}{14})

reshalka.com

Математика 6 класс Виленкин. Номер №454

4 \frac{11}{18} * \frac{6}{7} - 1 \frac{4}{9} = \frac{83}{18} * \frac{6}{7} - 1 \frac{4}{9} = \frac{83}{3} * \frac{1}{7} - 1 \frac{4}{9} = \frac{83}{21} - 1 \frac{4}{9} = 3 \frac{20}{21} - 1 \frac{4}{9} = 3 \frac{60}{63} - 1 \frac{28}{63} = 2 \frac{32}{63}

(1 \frac{1}{2})^{3} - 2 \frac{1}{4} * 1 \frac{1}{3} = (\frac{3}{2})^{3} - \frac{9}{4} * \frac{4}{3} = \frac{3}{2} * \frac{3}{2} * \frac{3}{2} - \frac{3}{1} * \frac{1}{1} = \frac{27}{8} - 3 = 3 \frac{3}{8} - 3 = \frac{3}{8}

((1 \frac{1}{4})^{2} - \frac{5}{8}) * 10 \frac{2}{3} - 7 \frac{1}{3} = ((\frac{5}{4})^{2} - \frac{5}{8}) * \frac{32}{3} - 7 \frac{1}{3} = (\frac{5}{4} * \frac{5}{4} - \frac{5}{8}) * \frac{32}{3} - 7 \frac{1}{3} = (\frac{25}{16} - \frac{10}{16}) * \frac{32}{3} - 7 \frac{1}{3} = \frac{15}{16} * \frac{32}{3} - 7 \frac{1}{3} = \frac{5}{1} * \frac{2}{1} - 7 \frac{1}{3} = 10 - 7 \frac{1}{3} = 9 \frac{3}{3} - 7 \frac{1}{3} = 2 \frac{2}{3}

(1 \frac{4}{9} + 2 \frac{5}{6} - 2 \frac{3}{4}) * (2 \frac{1}{2} - \frac{11}{14}) = (1 \frac{16}{36} + 2 \frac{30}{36} - 2 \frac{27}{36}) * (1 \frac{21}{14} - \frac{11}{14}) = 1 \frac{19}{36} * 1 \frac{10}{14} = \frac{55}{36} * \frac{24}{14} = \frac{55}{3} * \frac{1}{7} = \frac{55}{21} = 2 \frac{13}{21}

ГДЗ Математика 6 класс Виленкин, Жохов, Чесноков